Recent content by lc99

Are there any other formulas i need for this. So far i am using W =Th-Tc and e = W/Qh After writing out the individual engines and calculating the work based on the previous i have: (Th-W1-Tc) /Th

I think since here we are dealing with carnot, can i say W = Th-Tc?

When i calculate the work for one engine, is it just the difference of Qh-Qc?

So far i have Engine A (between TH and TM) a e = 1-TM/TH. For engine B (between TM and TC) , e =1-TC/TM

not long if you know what you are doing! I do get it now. I didn't recognize that was about harmonics.

So i have a question. In terms of difficulty, how difficult is this question for an exam?

Why is it the product?

Okay, 1.5 m? right. And it's because we know that consequtive harmonics help us find the n

for 5th harmonic, wavelength = 2L/5 for 6th harmonic, wavelength = 2L/6 = 1L/3

5th and 6th harmonic?

Lambda = 2L/n?

Ahh man. I did not do that. Uhgh. No wonder nothing matched up. I did all the steps that needed to be done like finding the equations for shear and bending moments. But it just did not match up with the actual problem. UGH

For normal force A , i got like -474 kN . So basically i got the wrong support forces and so i used the wrong numbers.

I think the wavelength is 2L = lambda. for fundamental next harmonic is L = lambda

All i understand now is that the number of antinodes give a certain length. So for the consecutive frequencies, the antinodes are responsible for making the lengths equal