Homework Statement
2. Homework Equations [/B]
So the sample mean is 2. the sample variance would be [[(3-1+1)-1]/12]/36 = 8/432.
The Attempt at a Solution
Is it, P[ (2.1-2)/sqrt(8/432) < z < (2.5-2)/sqrt(8/432)] = 0.232574.
The book answer is 0.2312. I just want to be sure.
What is the difference between "tangential and normal components" and "radial and transverse components" ? I mean in both cases, the two components are perpendicular to each other and one of the components causes the particle to rotated around, the other one gives it a speed to rotate with.
Is...
Okay, so, I can do arccos (0.131054) = 82.47, but the other angle that would also satisfy this would be -82.47, or 277.53, now substracting 55, i would get 222.53 for alpha. This 222.53 would result in a resultant vector of 600N, but how do i know, in between 27.47 to 222.53, the resultant...
mm, okay I followed your procedure, and I was able to get 27.47 as the angle for which gives 600N like this:
setting x = alpha + 55
sum of y-axis = sin x
sum of x-axis = cos x + 1.838
600/272 = 2.20
so, 2.20^2 = sin^2 x + cos^2 + 1.838^2 + 2*1.838*cos x
it simplifies to 0.131054 = cos (x)...
Homework Statement
http://puu.sh/4NWw9.PNG
question 2.65**
Homework Equations
I've tried using the law of sine and law of cosine method with the triangle for equilibrium and I've tried the 600^2 = Fx^2 + Fy^2
The Attempt at a Solution
Here is what I did using the F^2 = Fx^2 + Fy^2...
Homework Statement
Use differentiation to find a power series representation for
f(x)=1/(1+x)2
Homework Equations
The Attempt at a Solution
1/(1-x) = \sum(x)n
1/(1-(-x)) = \sum(-x)n
Deriving 1/(1-(-x))
-1/(1-(-x))2= \sumn(-x)n-1 from n=1 to infinity
indexing it from...
Homework Statement
http://puu.sh/1rcsO
I got the first one from a simple scaling, but I can not figure out the second one.
Homework Equations
Det(cA) = cDet(A)
Scaling a row scales the determinant
Adding rows/columns to each other does not affect the determinant
Det(AT) = Det A...
*new question, playing with projection matrix.
Well I have a new question about the A(ATA)-1AT matrix.
http://puu.sh/1jXT6
I was able to show that BT was idempotent, but my manipulation was a bit different from the teacher for B2
Let B2 = (A(ATA)-1AT)(A(ATA)-1AT)
I did...
They say that electrons move from the higher potential to the lower potential. For example, in this situation.
Q1 and Q2 are negative charges and Q3 is positive. But, the equipotential is lower on the Q1 and Q2, so by definition of potential difference, the electron would go from the...