Recent content by littledude565

Ah yay, thanks for all your help

http://img24.imageshack.us/img24/9337/71116538.png

ohhh no it should be 45 it should also be 30! So with that now would the resultant be 42.2, with an angle of 45?

http://img21.imageshack.us/img21/7229/83881376.png

ah thank you very much. So would that mean the resultant of these would be 54.08? I got that using phythag sqrt 45^2+30^2 = 54.08 with an angle of 34

ok so if the verticle velocity increases by 10 every second, would the answer then be 30m/s?

so what equation do i use now? :S

Ok using the s=1/2*(u+v)*t i did 45=15t, t=45/15 and so i got 3seconds. Is that correct?

in your equation x = 1/2*g*t² So using that i did (assuming the G did stand for gravity). 1/2 * 10m/s*4.5s^2 and i got an answer of 101.25

and the horizontal 30m/s as its a constant?

the g stands for gravity right? if so would the answer for the verticle be 101.25?

Homework Statement Tom throws a ball of a cliff 45m nigh, with a velocity of 30 m/s. Take accleration due to gravity as 10m/s. (It took 4.5s to reach the bottom) What was its horizontal and verticle velocitys when it hit the ground? i used the first equation (v=u+at) and with substituion...