Isn't the relative velocity equal to zero in this case in which "point A is attached rigidly to the moving frame" respect to which its coordinates do not change?
If that is correct, the velocity of transport should be equal to the absolute velocity of point A in the descibed scenario.
Consider the external force and moment acting on the whole mechanism first.
One is the represented M, which is necessary to raise the combined mass of 50 kg, which can be represented as a vertical force applied at point G.
Note that the value of that vertical force will be constant, while the...
You are welcome, Charles.
Please, take a second look, right triangles are hidden in your diagram:
See the Thales' theorem in the following link:
https://www.mathsisfun.com/geometry/circle-theorems.html
:cool:
I located the center of the R = 11.0 largest blue circle at the point I knew with certainty, which was the interception of the of the R = 2.0 smallest blue circle and the R = 7.0 magenta circumcircle connecting all the vertices of our polygon.
Because there is the vertical constant acceleration of gravity, the direction of the total acceleration of the weights, regardless its magnitude, can never reach a horizontal direction.
In that case, the solution can't be applied to modern direct injection into the combustion chamber, only to carburetors and injection into intake manifold.
Then, expect a slight increase in the volume and pressure of the heated mix, both of which should be working against the airflow and...
One problem has been keeping the fuel from reaching the boiling point in hot conditions.
Please, see:
https://www.onallcylinders.com/2015/08/07/ask-away-with-jeff-smith-understanding-vapor-lock-and-how-you-can-fix-it/
Because molecules of the liquid will be jumping into the gas space as long as they have extra energy to do so.
Those jumps will increase if the pressure of the gas decreases and/or the temperature of the liquid increases.
Each substance shows a different dependence rate on pressure and...
Not what I wrote. :smile:
When the level reaches 10 meters, some pressure value may still exist on top of the water, which should be considered.
Besides the weight of the 10-meter column, the tap will be "feeling" that pressure (which is transferred through the incompressible liquid).
Try...
Because the reasons explained above, statement (i) is only approximately correct.
Please, see:
https://www.aps.org/archives/publications/apsnews/201210/physicshistory.cfm