Recent content by lorx99

Oh i think i understand. Does this involve len's law to figure out the direction of the induced current? Once we know the direction of induced current, the electric force (electric field caused by changing magnetic field which causes the induced current is along the direction of the charge...

The emf produced is equal to the negative rate of change in flux

Is it moving left because the induced current is clockwise and so the electric force is left at tbat point or some other reason?

Homework Statement Homework Equations Right Hand Rule The Attempt at a Solution I am not understanding why the force is left. I can only figure out that the current in the solenoid is moving clockwise because of the right hand rule. From there, I see that the induced current might be...

Thanks, i entered the E-6 wrong! answer is -150e-12

I aciddently left out that i multiplied by 10^-6 for the product of q's. But the answer is right.

Homework Statement Homework Equations U=kq1q2/r The Attempt at a Solution W = changeU = Uf-Uo Uf = k(7*(-5) + 7(-4) + (-5)*(-4))/0.1 = -4.3*10^-4 Ui= k((7*(-4))/0.1= -2.8*10^-4 Uf-Ui = -1.5*10^-4k J

I guess that is why I am confused. The pic was part of a lecture slides since it was a iclicker question. There is no original figure unfortunately. I do know that the answer is A) Edit: I get it now. I don't think the picture is really helpful. Redrawing the diagram based on the description...

Yes, i learned about Gauss's law. Then i would have to find the charge based on the charge density? Wouldn't there be two regions of differing charge density? edit : E = (p*V1 + p*V2)/ ((4pi*r^2)*episilon*)

Homework Statement Homework EquationsThe Attempt at a Solution I am having trouble figuring out why the answer is A) the electric field points radially between A and B. I think it is because since the point between A and B is mostly negative, the electric field would point outwords more...

Ehh. It's not really homework. I'm doing a bunch of practice exams to prepare my exam tomorrow. So the answer seems to be e) but is the kp/sqrt() just a constant then? and can be taken out of the integrals? The integral only depends on the limits of the box right?

How do i deal with the d^3(r)? Also, is the absolute(r-r') just the sqrt(x^2+(y'-y)^2+z^2)?

Homework Statement Homework Equations dV= integral(kdQ/dR) The Attempt at a Solution So, I'm familiar with these type of problems but in 2D (like a line of uniform charge). When the y,z component is added, I'm kinda lost. i know dQ = p*dV= p*dx*dy*dz. (atleast i think it is). also the dR =...

Homework Statement Homework Equations E=KQ/R^2 The Attempt at a Solution I'm kinda confused at what the question is asked. It is in terms of x, but I thought the integral for potential is V=int(Edr)? Also, should it be integration starting from infinity? Why is the integration from -2 to 3...

Is there a more conceptual way to explain this like with the fringes? I just don't do well with equations/proofs that explain concepts :/.