Recent content by lostie100

F = Gm1m2/r^2 but doubling the mass doesn't double the force.

A satellite orbits a planet. The gravitational field strength at the radius of the orbit is 12 N/kg. What will the gravitational field strength at the position of the satellite be if - The planet's density is doubled? - The satellite's mass is doubled? I just don't understand their...

Ok. At a depth of 1000m, the ocean temp is 4 degrees celsius and the speed of sound is 1480m/s. From lab experiments, for every 4m/s increase in velocity, the temp increases by 1 degrees. When the distance is 8000km, the smallest time change that can be detected is 1s, what is the smallest...

The mass also doubles...but I don't see how it relates to the other formula for velocity...

A wave travels with speed 200m/s. Its wave number is 1.5rad/m. What are its wavelength and frequency? distance = wavelength x # of wavelengths v=lamda(f) 1m = 1.5 (lamda) since in 1 meter there was 1.5 waves. 1/1.5 = 0.66m 200 = 0.66 (f); f = 300Hz. But this is wrong. I don't know...

A wave travels along a string at a speed of 280m/s. What will the speed if the string is replaced by one made of the same material and under the same tension but having twice the radius? V = root (Tension/mu) mu = mass/length length is 2radii I manipulated the formulas, however...

Thank you very much! Also, how do you determine the sign of the velocity? It doesn't say whether it is going forward or backward...

ohhh x should be 1.2-1.0=0.2m http://session.masteringphysics.com/problemAsset/1001073/10/knight_Figure_14_36.jpg Can you explain to me what the length from 0 to 0.6m is for? Is that the part that is not stretched at all?

I used (1/2)mv^2 + 1/2kx^2 = 1/2k(A)^2 since at the length 1.2m, the total energy in the system should equal the potential energy at the amplitudes. So, I just plugged in 54.7kg as m, 240 as k and 0.4m as amplitude and 1.2m as x. The amplitude concerns me because if I use x(0) = Acos(theta)...

Hmm right. I thought it was constant for some reason. I know it's not. Okay, I'm not getting the right answer though...The diagram is shaped like a W with the highest point at 1.4m and lowest point at 0.6m. Lasts for 6 seconds...2 oscillations...

But how can a velocity of -2.37m make sense if the minimum distance from the equilibrium is 0.6m and that 1 oscillation takes less than a second?

Astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating on a large spring. Suppose an astronaut attaches one end of a large spring to her belt and the other end to a hook on the wall of the space capsule. A fellow astronaut...

I just have a simple question as to which radians to use in calculating phase constants in oscillations. For example in sin(theta) = 1/2, do I use the (pi)/6 or 5(pi)/6? The exact question has a diagram and is difficult to explain, but I just want a general explanation. Thank you!

I don't quite understand this problem. I know the formulas to use, but I'm confused as to which mass I should use in the w=root (k/m) equation. Also, the force of friction is around 4.9N, would that also be the block's acceleration? what would that do?