Recent content by lukasz08

find the points of discontinuouty limit as x,y ---> (0,0) of function f(x,y) = 1-((cos(x^2+y^2)/(x^2+y^2))

Does anyone know how to find the answers ?

Tension = 386lb Bx = 493lb By = 186lb I am having trouble trying to determine the tension in the picture. And the x and y component of B i have a long bar that is 14 feet long. it is connected at 1 end at point B to a pin support and the other end is tied to a rope at point a.point a the rope...

Nevermind i have figured it out

Homework Statement A_________B____________Wd_________Wp_ |--1.2m--|----1.2m------|---2.2m-----| Above is a diving board with 2 weights on it. determine the reactions of A and B wd= 36kg = weight of diving board wp= 54kg = weight of person standing on...

can you somehow factor the following equation ? sqrt(9sin^2(t)+16cos^2(t)+1/4)

ok i got it mvi = -mvf therefore -mvi - mvf = -2mvx

yes i understand that so the second negative appears after the particle has hit the wall resulting in the 2mvx ?

p=momentum=(mass*volume) delta px = pf - pi mvf - mvi mvx - (-mvx) <<<<---- where does this second negative come from ? what am i missing here? 2mvx in my book it shows that delta px = - mvx - (mvx) = -2mvx

hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ?