# Calc based physics thermodynamics

1. Oct 3, 2008

### lukasz08

hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ?

2. Oct 3, 2008

### stewartcs

It depends on the process path. If you assume it is a constant pressure process, then the boundary work is just $W_b = P(V_2 - V_1)$.

CS

3. Oct 3, 2008

### jasc15

You integrate the pressure with respect to volume. Depending on the process (isobaric, isochoric, isothermal, isentropic) this function (p = f(v)) will be different. These functions can be derived using the ideal gas law.