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Calc based physics thermodynamics

  1. Oct 3, 2008 #1
    hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ?
  2. jcsd
  3. Oct 3, 2008 #2


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    It depends on the process path. If you assume it is a constant pressure process, then the boundary work is just [itex]W_b = P(V_2 - V_1) [/itex].

  4. Oct 3, 2008 #3
    You integrate the pressure with respect to volume. Depending on the process (isobaric, isochoric, isothermal, isentropic) this function (p = f(v)) will be different. These functions can be derived using the ideal gas law.
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