lukasz08 Messages 10 Reaction score 0 Thread starter Oct 3, 2008 #1 hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ?
stewartcs Science Advisor Messages 2,176 Reaction score 3 Oct 3, 2008 #2 lukasz08 said: hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ? It depends on the process path. If you assume it is a constant pressure process, then the boundary work is just [itex]W_b = P(V_2 - V_1)[/itex]. CS
lukasz08 said: hi. i was wondering on how to do this integral. W= - integral Pdv. what is the integral of dv ? It depends on the process path. If you assume it is a constant pressure process, then the boundary work is just [itex]W_b = P(V_2 - V_1)[/itex]. CS
jasc15 Messages 162 Reaction score 5 Oct 3, 2008 #3 You integrate the pressure with respect to volume. Depending on the process (isobaric, isochoric, isothermal, isentropic) this function (p = f(v)) will be different. These functions can be derived using the ideal gas law.
You integrate the pressure with respect to volume. Depending on the process (isobaric, isochoric, isothermal, isentropic) this function (p = f(v)) will be different. These functions can be derived using the ideal gas law.