1. True
2. I'm not quite sure what "the external pressure exerted by the inside face" means- does that mean the pressure that the internal gas exerts on the exterior? If so, I would say True but only in a reversible process.
Summary:: Basically the title: It seems that one of the formulas I use considers the pressure in PdV to be internal, when as far as I know, it is external.
So to my understanding, in w = PdV, the pressure is the external pressure.
However, I get tripped up because in my textbook, for a...
So I've gone and tried ##f(t) = Ce^{\frac{-t}{2\tau}}##, but that does not give me the correct answer. It actually comes close, but I get ##E^2## instead of ##(E - \hbar \omega_{21})^2## like my answer is supposed to be (correct answer in OP), which makes me suspect my electric field expression...
Fair enough. For some reason I thought there would be another term that also has some other kind of dependence, along with ##f(t) = C e^{-t/2 \tau}##. How in the world do I go about finding C though?
No, I'm being told to start by taking the Fourier transform of the emitted field, and as far as I'm understanding, I won't even be using the einstein coefficients.
I'm being told to calculate the Fourier transform of the emitted field to find the frequency spectrum of the radiated power, and...
All I'm reallly confused on this problem is what the expression for the emitted field is. As long as I've got that, I'm good to go, but I just don't know what to use. I've tried looking for an expression for the emitted field but I've had no luck. Would appreciate any ideas or someone telling me...
Wow. I can't believe I missed that. Thanks a ton.
So for this, would the wavefunction ##\psi_{nk}## just be ##\psi_{nk} = \psi_n(x_1)\psi_k(x_2)##?
For distinguishable particles I don't even care about spin right? Just that they're distinguishable?
I'm having a hard time understanding how to treat fermions, bosons, and distinguishable particles differently for this problem.
To the best of my understanding, I know that my overall state for bosons must be symmetric, and because they're spin-0, this means there's only one coupled spin state...
These days I've taken an interest in lithium ion batteries and the like, but I don't really know where to go to start learning about them. I saw the general engineering sources and the materials/chemical engineering sources threads, but there was nothing specifically about batteries- Does anyone...
This made a ton of sense! Thank you so much!
Couple questions:
When you were redefining ##\hat{\Psi}##, where did the ##\hbar^{3/2}## come from?
Also, given that I'm now using ##\hat{\vec{x}}##, does that mean that the units of my displacement are whatever my displacement units originally...
For context, something I'm doing is just solving schrodinger's equations for particles in boxes, but it's suggested that I set hbar = 1, in order to make numbers easier to handle/look at when plotting. However, I just don't get how setting hbar = 1 affects my other units/variables- I don't...