Recent content by maggas

I've managed to solve this myself, thanks for the help :cool: \textbf{B}=(\hat{\textbf{k}}\times\textbf{E})/c c\textbf{B}=(\hat{\textbf{k}}\times\textbf{E}) Then using Lagrange Triple Product \hat{\textbf{k}}\times(\hat{\textbf{k}}\times\textbf{E}) =...

Homework Statement In this tute on EM waves, we were given the Electric Field \textbf{E}=\textbf{E}_0\text{exp}(i(\textbf{k}\cdot\textbf{x} - \omega t)) which after a fair bit of algebra yields the magnetic field \textbf{B}=(\hat{\textbf{k}}\times\textbf{E})/c Similarly the inverse...