Recent content by Maggie
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Explosion energy dissipation and Ek
Yes I got the same answer, but this equation is more abstract to me, I like that momentum method better:)- Maggie
- Post #26
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
thank you! so tricky this question- Maggie
- Post #24
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
okkkkay thanks. but just to confirm my calculation. the initial Ek will be 0.5*9.6*(14.6)^2=1023.168J, and the final Ek for m1 is 0.5*9.4*14.962^2=1052.149J, since energy is scalar, the direction doesn't matter, the final Ek for m2 is 0.576J, the total final Ek is 1052.725J. And the difference...- Maggie
- Post #22
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
okay now I understand, but once I got the final velocity of m1, what should I do next? using EK equation?- Maggie
- Post #20
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
do you mean that the m1+m2=9.6kg? So actually m1 is only 9.4kg? oh I misunderstood all the time... so the initial momentum is 9.6*14.6=+140.16kgm/s, then the final would be (140.16+0.48)/9.4=14.962m/s?- Maggie
- Post #18
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
ohhh I just knew that energy is scalar but forgot about momentum... okay. So the final momentum of m1 would be (143.08-(-)0.48)/9.6=+14.954m/s, right?- Maggie
- Post #16
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
Now I got it clearer, so the initial momentum is (9.6+0.2)*(14.6)=143.08, and the final momentum of m2 is 0.48, so the difference is 142.6, then 142.6/9.6=14.854m/s, this is the final v of m1. Then how can I deal with this final v?- Maggie
- Post #14
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
Do you mean that the momentum of the two masses before should be calculated by v(m1+m2)? which is 9.8*14.6?? But I don't understand why the initial momentum should include both masses...- Maggie
- Post #11
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
is the momentum calculated by mv? then: momentum of the mass before= explosion momentum+momentum of the mass after? and initial momentum is 140.16 and final is 0.48, the difference is 139.68- Maggie
- Post #9
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
I only know that the momentum should be conserved since no external force applied, so the difference between pi and pf should be the momentum of the explosion? I'm confused now...- Maggie
- Post #7
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
but how? I calculated the initial p is 140.16 and final p is 0.48, the difference is 139.68, how can I transfer this answer into energy?- Maggie
- Post #5
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
I remembered energu conservation, momentum conservation, and probably charge (not relevant)... should I use momentum in this question?- Maggie
- Post #3
- Forum: Introductory Physics Homework Help
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Explosion energy dissipation and Ek
Hello, I think the only energy involved is kinetic energy. So I subtract to get the difference between two stages to find the energy cost by explosion. (0.5*9.6*14.6^2)-(0.5*0.2*2.4^2)=1022.59J However the system said that this answer is wrong, So I wondered where did I make a mistake?- Maggie
- Thread
- Dissipation Energy Energy dissipation Explosion
- Replies: 25
- Forum: Introductory Physics Homework Help
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Rational motion combined with 2 springs
Thank you so much now I got that!- Maggie
- Post #7
- Forum: Introductory Physics Homework Help
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Rational motion combined with 2 springs
I think the force, is that centripetal force of Block B only?- Maggie
- Post #5
- Forum: Introductory Physics Homework Help