Recent content by Mahbod|Druid

Isn't the fourth derivative of position "acceleration of accelerate" ? like : g is the third derivative of position in falling g = GM / R^2 dg / dt = dg/dR * dR/dt = -2GM/R^3 * V (vector that points top is + for Velocity) so g is chanching with dg/dt rate ?

The problem is indeterminate m = 0 withouth any calculation because the central star is a Dot Gravital point at it can not create coriolis/euler(i think) and if there are other stars around it will be indeterminate for sure Here is the only way that problem will not be...

Is spin of Earth constant during year ? (don't implant friction(s) )

Aha got it I assumed we know what : Acceleration(y) and Acceleration(x) thats why [theta] was known in my calculation but if u just told that ay/ax is not known it wouldn't get this long :D thanks 4 ur time

Sorry for my poor English ... :shy: here in this pic : Do you agree that eccentricity is uniqe for a given Velocity(+ vectors) and acceleration (+ vectors) ? and we can find eccentricity from : e/Sin[theta] + Cotg[theta] = -Vy/Vx and we can find w : V Sin(X) / R (X was shown...

I just gave an example for circular because it was easier the Velocity given by Questioner(?) and vectors given must be currect if not it will fall on the star / run away from star and the Questioner already mentioned that it is a Ellipse so it is uniqe look @ page 2 or hallosivy they...

it is not indeterminate since Velocity vectors and Acceleration vectors are known its like saying at the distance of R and Mass of central star = M , we will have acceleration = K also at the distance of 2R and Mass of central star = 4M we will have same acceleration = K but we know...

Hi as Gravity Force always points to Sun (from Earth to sun) and there is no other force there will be no acceleration in e[theta]vector (e[theta] vector makes 90 degree with er) so there will be no coriolis force or Rw' that's why i said all the sentences with e[theta] in it equals to...

Ive said how to find "w" in my post "page 2" next to Picture also "wt" which is [tex]\theta[tex]

and for finding "e" i think this is the answer : (in ellipse) -(e/Sin[theta] + Cotg[theta]) = |Vy|/|Vx|

oh... Latex errors ... at the end of Velocity that is e\theta not that Click on the Latex images and read there and for : \theta = 180 - A it was a exception for this picture it depens on which quarter u want to calculate it may become like 180 + A

http://www.picamatic.com/view/3620071_ellipse/ and w = V Sin X / R :edited X: and from Polar Direction we have : R er => derivate (d f(x) / dt i`m not sure about the English word) Velocity = R' er + Rw e(theta) => derivate again for acceleration R'' er + R'w e\theta+ R'w...

Hi "2- acceleration" u mean we have R'' ? (R'' = d2R/dt2) or we have GM/R^2 = acceleration ? + velocity

on surface ? but Wire has not any Extra charge so why should electrons go on surface ?

Hi I have read Bio-Savar , Amper law (also maxwell) about Magnetic fields but all of them had I bio-savar : B = \frac{\mu0}{4\pi } \frac{ids Sin\theta}{r2} Amper : \int B.ds = Iin \mu0 but what about a Electron moving in a line path ? how big will be its magnetic field ? it...