Recent content by Malcohmh

  1. M

    Finding the delta x of a bow and arrow pullback

    It's (1/2)•444.8•Dist.=(1/2)(.04)(82.6^2) Yes! Distance=.61meters!
  2. M

    Finding the delta x of a bow and arrow pullback

    Ya. I think I am missing some pieces.. from what I see towards the end of the video. :D 136 joules of KE= 1/2m(82.6^2). m=.04kg then i plug that into 444.8xDist.=1/2(.04)(82.06^2)! YES?! The pullback is .3m?!
  3. M

    Finding the delta x of a bow and arrow pullback

    No the pull on the bow! Sorry lol... Idk what I should plug in? Does that mean I have to solve for the mass in KE?
  4. M

    What inspired me to study physics?

    I was inspired by my really cool AP Physics teacher and by watching the Interstellar movie! HAHA
  5. M

    Finding the delta x of a bow and arrow pullback

    So I ended up using work= kinectic energy, because it's the same. I got (444.8xDistance)=1/2(45.36)(82.6^2) then i got a very large distance? was that right?
  6. M

    Finding the delta x of a bow and arrow pullback

    Homework Statement Find the delta x of the bow pullback. The weight of the pullback is 45 kg, the speed of the arrow as it shot out was 184mph( i converted that to velocity and got 83 m/s). Homework Equations I'm using K1+U1+W=K2+U2. The Attempt at a Solution I wasn't sure which formulas to...