Recent content by MaratZakirov

Hello everyone, I must admit that I recently failed to find exact solution for equations I wrote above. I can of course make a brute-force or even gradient based solution, but exact analytical solution I can not, I am already spent too much time for it. So if you have some ready to show...

Let's look at my first post Maybe I should be more explicit?

Let's separate the patties from the flies. The inertial frame of reference associated with the car before the collision is not accelerate. After the collision, the car will have a velocity different from ##\vec{0}## in this system. Maybe you want to say that: a) I didn't write equations...

I completely miss your point (https://en.wikipedia.org/wiki/Inertial_frame_of_reference) I do not see anything simple in simultaneously using two coordinate systems, one tied to the sail and other to the rail. A solution in a system with a rail at rest must be obtained in a trivial way after...

Please prove your statement, it is totally not obvious to me. But I agree that fewer claims is better, so let's write equations without it: 1. Momentum conservation parallel to sail (no friction with sail) ##m_p\vec{v}_{p \perp s} = m_p\vec{v}_{p \perp s}^1## 2. Momentum conservation along rail...

(I tried to edit my answer, but now I can not, so I make this post) Yes, I agree, but I view on this in slightly different angle. Conservation of moment is always the case but in te ##\vec{v}_{p \parallel s \perp r}## direction there will be interaction with the planet Earth itself, so I claim...

I finally have the solution (whether it is correct or not, I expect you to judge) Given: ##\vec{v}_p## and ##m_p## initial velocity and mass of particle. ##m_c## is the mass of car which is on rail with unit vector ##\vec{r}## direction and unit (with length equal to 1) vector ##\vec{s}## as...

What is the physical reason to ##\vec{v}_{p\perp}^1=\vec{0}## be true? In similar case particle and wall it is not true.

Let's concentrate on the first collision. Later on, we can always select a new frame of reference linked to a car before the next collision, for computer simulation purposes (if you're asking about that) it's not a problem at all to make such transformations just substitute car velocity when...

First I must say that in equation you wrote ## \vec{v}_{c\parallel}^0 = \vec{0} ## because the frame of reference is linked to the car before the collision and car do not have any velocity whatsoever before collision. Angles are set by unit direction vectors ##\vec{n}## is normal to rail...

Any possible normal to the rail component of velocity of that object? Or both? How momentum conservation equation look in this case?

What is "reaction impulse"? Could you please kindly write some equations? Or maybe you provide links to some motivational examples similar to my case?

My thoughts were the following: I took momentum conservation equation: ## m_p\vec{v}_p^0 = m_p\vec{v}_p^1 + m_c\vec{v}_c ## then I made a scalar product for both sides of it ## <m_p\vec{v}_p^0, \vec{n}> = <m_p\vec{v}_p^1 + m_c\vec{v}_c, \vec{n}> ## simplified it a bit ## m_p<\vec{v}_p^0...

I solve the following problem, there is a particle of mass ## m_p ## and velocity ## \vec{v}_p ## which collide with sail installed on rail car with mass ## m_c ## resting in the frame of reference associated with it before the collision. The cart is fixed on straight rails for which the vector...