Recent content by marcmtlca

maybe you could use nonparametric methods?

note: If the mgf exists in a neighborhood around 0 then the characteristic function = mgf(i*t)

I wrote the first exam and got a 2/10. The second time i studied and passed. It's not that bad, they just make sure you have no time to think on the exams. As for the job itself, I have no idea. M

ya so if your n is not large enough, the approximation is not comfortable enough to use the normal. that's fine.

that looks like a negative binomial distribution... not sure. but you should probably prove it sums to 1.

\Large \sum_{x=10}^{18}(.5)^x(.5)^{18-x}

simply put: under certain regularity conditions (finiteness of mean and variance), given Y_i are independent and identically distributed random variables. \frac{\sqrt{n}}{\sigma}(\frac{1}{n}\sum_{i=1}^{n}Y_i-\mu) \rightarrow N(0,1) You can think of the Y_i as fish that you are sampling...

Take Linear algebra, calculus and Differential equations. Then take an Analysis class and an Abstract Algebra class. Follow this up with a high level honours probability class. After all this you should be able to teach your kids some math

Teaching students about 1-forms is ridiculous. They should just learn to "do" calculus. When they have gained some mathematical maturity then they can be treated as adults. I remember that I had a rough time in my differential geometry class despite having been a math student for 3 years

99,999 is divisible by 9 but the digits sum to 45.

why don't people disagree with 1.000...=1. seems almost the same as .999...=1 to me.

I agree with mathworld.

I believe the question is only asking for the number of solutions to: x_1+x_2+x_3+x_4+x_5=9 with 0 \le x_i \le 9,x_i \in \bf{N}.

Usually when you see something like \frac{1}{\sqrt{1+x^2}} or \frac{1}{\sqrt{1-x^2}} or anything similar then you can think about using a trig sub. I usually think of trig sub when I see somethign that looks like the derivative of an inverse trig functions. (you should memorize those). But...

Consider a matrix A_n such as the one you described with n \geq 3. Look at the columns of A_n: the first column, c_1 looks like: c_1=(2,...,n+1)^T the next column looks like c_2=(3,...,n+2)^T and the third column looks like c_3=(4,...,n+3)^T. Since we took n \geq 3 we know that we can...