Recent content by masqau

dear i am sending the link of a book written by Abramowitz and Stegun. hope this will solve ur problem, Good luck http://calc.entisoft.com/Go/ConvertIt/Reference/AMS55.ASP?Res=150&Page=722

How about if i put y=exp(-x)J(x) hope it works...

substitute the value of ground state wavefunction and integrate it. thanks for making my equation nice...

$$E10=\int \psi_{0}^{*}(x)x^4\psi_{0}(x)$$

U have prove that u be my swami not i be ur swami. Nice to meet u Swami Vivekanand.

Frobenius don't work because of log(x) and its sigularity. from variation u mean chnage of variable, its also don't work because chnage of variable create image on the other term, like exp(x) have image of log(x) and vice versa. Green function can be helpful, can u explain it please?

u r right the singularity is at x=0. from limit range u mean, to expand the log(x) into to its series form and than take first two or three terms. u know this problem is very interesting in the sense that it show the clash of linear and exponential behavior. if the DE is y''+(n^2+x)y=0, (1)...

U welcome

Actually their claim was for the complete description of wavefunction some hidden varibale is needed, which Bell's shown that if there is a wavefunction there is no hidden varibale anymore. "I am therefore i think. I think therefore i am." (How i can teach the native of F. Nietzsche).

i/delta is Feynman propagator. since field theory is relativistic hence all the expression must be Lorenz Invariant.

what Spukhafte Fernwirking mean...

EPR-Hidden variable. Yes i know ...Bell's experiment already reject this EPR.

Because Einstein don't know about entanglement at that time. Moreover, he don't want some one challenge his theory except Fock and Dirac attack his theory.

Consider the interaction of field and atom, whose wave function are correlated mean u cannot separate the wavefunction of atom from the wavefunction of field, hence they are entangle. change in one will automatically bring change in the other.

Thanks Torquil. U know the original equation was, Y''+xy+n^2y+exp(-x)y=0, when i used the transformation x=exp(-z/2), i got z^2y''+zy'+(z^2-n^2)y+ylog(z)=0, which i already post, now according to u if z=log(u), than i am sure i will get my original equation (1), with exponential.