Recent content by mathmajo

Since an --> 0, given some epsilon>0, there exists and m>0 such that /an-0/=/an/<epsilon for all n>m thus, /bn-b/</an/<epsilon for all n>m therefore, by definition bn-->b

Homework Statement If (an) — > 0 and \bn - b\ < an, then show that (bn) — > b Homework Equations The Attempt at a Solution