Convergence Induction for Positive Sequences: Proving Limit Behavior

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mathmajo
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Homework Statement


If (an) — > 0 and \bn - b\ < an, then show that (bn) — > b


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The Attempt at a Solution

 
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Since an --> 0, given some epsilon>0, there exists and m>0 such that /an-0/=/an/<epsilon for all n>m
thus, /bn-b/</an/<epsilon for all n>m
therefore, by definition bn-->b
 
mathmajo said:
Since an --> 0, given some epsilon>0, there exists and m>0 such that /an-0/=/an/<epsilon for all n>m
thus, /bn-b/</an/<epsilon for all n>m
therefore, by definition bn-->b

Looks ok to me.