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I think I got it now. if the height is 5 units = distance from line m to P. Then its is suppose to satisfy that (heigh*base)/2 = 20 meaning that (5*base)/2 = 20. Meaning that the base is suppose to be 8.
That must mean the distance from B to C is 8. Then I draw a circle with B as its center...
Just to understand your point. Since both B and C are on the l. Then the base of the triangle must be the distance from BC? If that that's the base. Then if I use the point-to-point distance formula, then I get a base of 9.8. And if the area of the triangle is 20 then the height is 9.8*height/2...
Thank you for your answer. I look at the text again and the point C is suppose to be on line l too.
So my question how or can I use the information that the area of the triangle is suppose to be 20 to find C? Or is that information redundant?
Let the point P(2,8) be a point in xy-plane and line m: y = -0.75*x+3.25 be a line in the xy-plan. The distance from a point P to a point B is 7 unites. Where the x coordinate of B is negative. Find the acute angle between PB and m.
To find B I then construct a circle of radius 7 with center...
x to increase to. But why do I get the maximum point if solve the internal function as eqn: t^2-48*t=0 and divide one of the roots by two? Is it only do to symetry?
I have tried to say I take the internal function y=t^2-48*t and solve y =0, then t^2-48*t = 0, then I get t = 0 or t = 48, and it looks to be the function is symetrical, so if I divide by 48 by 2, I get t = 24, and N(24) = 14648.13868 which looks to be a maximum. But is there a better way?
How would you go about finding maximum value for this function without Calculus? You can draw in it a CAS tool like Geogebra, NSpire or Maple. And use the maximise ability. But is possible to do it by hand? Pre-Calculus?
I have following differential equation dV/dt = 5 - 2 * V(t)^(1/3) which represents a the time its take to drain a barrel of rain water which contain 25 Liter of water, at t = 0.
I am suppose to calculate the least amount of water in barrel during this process.
If I set the rate of growth to...
I have the following DE, R'(t) = k*4*pi*R(t)^2, where R(0) = 5, and R'(0) =-0.001. I have attempted to solve it Maple, and would like to know if I have done it correctly?
Thank you again for your answer, no danish is a small language :)
I try again,
But if the function for the perimeter is 2*l+w + pi *w/2 = 8,(if we assume l is length of the square part, and w is the width) so that l = 4 - (9*w)/7
If I insert this into the function f(w) = w*( 4 - (9*w)/7) -...
Thank your answer, the image in the textbook in the included file. The text is in danish, but simply says: A flowerbed is comprised of a semi-circle and square. The perimeter of the entire must be 8 meters in total.
How long does the sides of the square part have to be? To get the maximum...