Thanks , how do I do that , do I pick two values between each interval and solve the normal way ??
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Thanks , how do I do that , do I pick two values between each interval and alive for each value
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I have been asked to finding the area of the graph of the function F(x)=(3x-\pi)\cos\frac{1}{2}x between x=-\pi and x=\pi
using integration by parts to integrate the function I get \int 2(3x-\pi)(\sin\frac{1}{2}\pi)+12\cos\frac{x}{2}
when I work out the integral for x=\pi and x =-\pi I get...