Recent content by Mathpower
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Finding Integral of a Divided Function (Hyperbola?)
Nice! I like the alternative (because its the only thing I understood) from LCKurtz...rationalising the denominator. The rest of it didn't make much sense...how can you integrate with a remainder! (I must be missing something) Thank you so much for all your help. P.S.: Sorry for not being able...- Mathpower
- Post #6
- Forum: Calculus and Beyond Homework Help
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Finding Integral of a Divided Function (Hyperbola?)
Hmmm...Thanks for the hint, but I don't get what you meant here... Isn't the numerator already being divided by the denominator and aren't they to the same degree anyway?- Mathpower
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding Integral of a Divided Function (Hyperbola?)
Homework Statement Integrate between y=0 and y=-0.5: ∫((y+0.5)/(0.5-y)) dy Homework Equations Can you please show me how to integrate it...Then I will be able to take it from there and substitute in the appropriate values. The Attempt at a Solution Quotient rule in...- Mathpower
- Thread
- Function Hyperbola Integral
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Double Integrate to Solve t+(d2t/dr2) = -5sin(r)
Please help me double integrate this... (so that I will have t = ... ) t+(d2t/dr2) = -5sin(r) Thank you... Also any advice appreciated as to how to go about solving 'separate the variable type questions'.- Mathpower
- Thread
- Integration
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
Opps... I meant tan-1 r+C Thank you so much for your help. Sorry for being lazy.- Mathpower
- Post #10
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
Oh wait is the answer: u because 1+tan^2 u = sec^2 u then = ∫1 du =u + C =tan(r)^-1 + C Thank you for your help.- Mathpower
- Post #8
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
Delete this. See below- Mathpower
- Post #7
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
NO idea! I tried r= tan u 1/(1+(tan u)^2)... Too me that just seems even more worse! Then (LET: < be integral sign/ integrand) = <1/(1+u) dr = <(1/(1+u)) (secu)^2 du = <((secu)^2/(1+u)) du Stuck... and my latex is not working as well? Have I typed the wrong code?- Mathpower
- Post #5
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
eumyang...thank you...yes that's what i meant.- Mathpower
- Post #4
- Forum: Calculus and Beyond Homework Help
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Integrating a complicated polynomial
Homework Statement Hi An integration question: t= 1/(1+r2) Can you please show me how to integrate with respect to r. Thank you. The Attempt at a Solution ∴t = (1+r2)-1 I then tried substituting u = 1+r^2 but that didn't work! Is there a trick with this?- Mathpower
- Thread
- Polynomial
- Replies: 9
- Forum: Calculus and Beyond Homework Help
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What Is the Correct Substitution for Integrating t = r(r^2 - 4)^5?
Hey, what is the warning for? what did I do wrong?- Mathpower
- Post #10
- Forum: Calculus and Beyond Homework Help
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What Is the Correct Substitution for Integrating t = r(r^2 - 4)^5?
Ok thank you so much. You are awesome! Hmmmm... is it just my computer or is tex not working?- Mathpower
- Post #9
- Forum: Calculus and Beyond Homework Help
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What Is the Correct Substitution for Integrating t = r(r^2 - 4)^5?
Would you please be so kind as to post just 2 or 3 here? Pleeeeeaaase...- Mathpower
- Post #7
- Forum: Calculus and Beyond Homework Help
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What Is the Correct Substitution for Integrating t = r(r^2 - 4)^5?
Apart from practice and experience (I do realize they are the main things...but apart from them)? Don't say nothing...surely there must be some trick?- Mathpower
- Post #5
- Forum: Calculus and Beyond Homework Help
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What Is the Correct Substitution for Integrating t = r(r^2 - 4)^5?
Awesome thank you... Is there a trick to substitution questions? ie: what is the best way to approach such questions?- Mathpower
- Post #3
- Forum: Calculus and Beyond Homework Help