Recent content by mattcom1
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Distance traveled with acceleration & deceleration
Interesting. Let me give it a go. X = V1avg * t1 + V2avg * t2 X = 0.5 * a1t1 * t1 + 0.5 * a2t2 * t2 X = (0.5 * -9.8 * 3) * 3+ (0.5 * 5.88 * 5) * 5 X = -44.1 + 73.5 similar numbers as the first way, but a different sign... Certainly something else to consider! Thanks!- mattcom1
- Post #8
- Forum: Introductory Physics Homework Help
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Distance traveled with acceleration & deceleration
Hmmm... The only formula I know for average velocity is: Avg Velocity = Distance/Time. Distance is unknown and Avg Velocity is unknown. Is there another equation for avg velocity that I'm not aware of?- mattcom1
- Post #6
- Forum: Introductory Physics Homework Help
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Distance traveled with acceleration & deceleration
I'm glad to hear I'm not too far off on the methodology. I'm going to stick with -ve for gravity. Yes, I believe that the deceleration is intended to be constant.- mattcom1
- Post #4
- Forum: Introductory Physics Homework Help
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Distance traveled with acceleration & deceleration
Homework Statement A man bungee jumps off a cliff and free falls for 3 seconds. The bungee cord stops the jumper in 5 seconds. How far did the man fall in total?Homework Equations X = V0t + 1/2at2 The Attempt at a Solution Xf = X1 + X2 X1 = V1it1 + 1/2a1t12 X1 = 0 * 3 + 1/2 * -9.8 * 32 X1 =...- mattcom1
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- Acceleration Deceleration Distance traveled Kinematics equations
- Replies: 9
- Forum: Introductory Physics Homework Help