Recent content by mawalker

2.04 m... so 20/2.04 = 9.8 rps...to get revolutions per minute we would multiply by 60 seconds again. 20/2.04*60*60, correct?

ok, so i would leave 2000 in meters. so 20m/.24m*60s = 5000 rps hmmm...

so 204 cm... and it goes 20 m/s, so every second it would go 20 m. or 2000 cm. so 2000/204*60 = 588 rpm?

wait, i mean... r would be half of 65 so 408/2 = 204 cm

2pi(r)... = 2(3.14)(65) = 408 cm

the red dot is at the bottom again. it is the amount of time that it takes for a full rotation, and how many of these rotations are present within the span of one minute.

the diameter of the tire is 65 cm. so if it was stretched out then it would be longer than 65 cm.

so 20/60* .65?

i mean... seconds /60!

time is in minutes... seconds * 60

revolutions per minute? correct?

Homework Statement A car tire is 65.0 cm in diameter. The car is traveling at a speed of 20.0 m/s . What is the tire's rotation frequency, in rpm? What is the speed of a point at the top edge of the tire? What is the speed of a point at the bottom edge of the tire? Homework...

grrr... gravity A rocket is launched straight up from the Earth's surface at a speed of 1.90×104 . What is its speed when it is very far away from the earth? plugging everything into the energy conservation theorem i came up with the exact same speed... I'm not sure what I'm doing wrong.

how do i go about finding out which direction the net gravitational force on the 20kg object is? i know it would be somewhere in between the two but i don't know how to figure out how many degrees it is.

i've never really understood vector addition all that much. do i just square both numbers and add them together, then take the square root?