I have tried to do it by part.
If I make u=cos(x^3), dv=x^5 dx , the grade of x, which is in the cos(x^3) , won't be reduce.
If I make u=x^5, dv=cos(x^3) dx , I can't solve the \int cos(x^3) dx.
I have thought if there is some way to make it look nicer (like u=x^3 ),but I still...