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Multivariate Calculus question

  1. Feb 10, 2009 #1
    Hi, could anyone tell me the steps to solve the following question:

    Find the solution of x'=Ax with the initial value

    -------1---------2 0 0
    x(0)=( 0 ), if A=( 0 1 -1 )
    -------1---------1 1 1
  2. jcsd
  3. Feb 10, 2009 #2


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    Don't you want to start by finding the eigenvectors and eigenvalues of A?
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