Thank you Stephen! You have a way with words! That's exactly the scenario and problem.
Each experimentally produced curve follows an asymmetrical "S" shape. These 550 experimentally produced curves have been fitted with an equation containing four constants to alter the function to fit each...
I have around 550 asymmetrical sigmoid curves fitted to a function with 4 varying coefficients. Each of these curves represent strength as a function of time and temperature for a different compound. Each compound is made up of varying substances at varying concentrations.
Overall, I have 550...
I understood about the values, but thanks for the heads up!
I finished my paper and I was wondering, if you all had the time, to look at page 3 and the bottom of page 5 to make sure I properly explained the integration aspect...
Alright. I completely understand the math thanks to http://www.youtube.com/watch?v=nNHlSB6b1HU".
But I have one more q before I call it a day. How exactly did integrating give us the answer in seconds?
Let me guess and tell me how wrong I am: by getting F=ma down to an acceleration...
I'm sorry, I am not in calculus based physics so excuse the ignorance :) Sound's like a differential equation. Newton's second is F=m * dv/dt. If this is a differential, how do I set this up to calculate via Wolframalpha?
Homework Statement
A 100kg skydiver has a terminal velocity of 58 m/s. Assuming air resistance of the skydiver is Fair=.3(v)2, how long will it take the skydiver to reach 58 m/s?
gravity is 10 m/s2 in our class btw.
Homework Equations
Fair=.3(v)2
Fg=mgThe Attempt at a Solution
I know the air...
Integrating twice makes sense. I could graph the formula twice integrated and find the change in x for a quarter oscillation, correct?
Thanks for the help guys.
Homework Statement
Find the time it takes for a particle initially at rest to travel around a circle with acceleration \ddot{\theta} = -3 \cos{\theta} to travel 1/4 of the circle.2. The attempt at a solution
\int_{0}^{{\frac{\pi}{2}}}-3 \cos{\theta}
Am I doing this right?