Recent content by ----md

I realized my mistake. SO I was assuming that the F of the crutches are like an external force. But its just a component of the mg. So I set it up as μmgsinθ=mgcosθ -> .9 tan-1= θ Thanks.

Does that mean that because he is standing- his weight isn't a factor in the upwards forces- because it gets canceled out? and the only net force is the vertical component of the crutch?

Hi All- Hope you can help me :| Homework Statement The person in the drawing is standing on crutches. Assume that the force exerted on each crutch by the ground is directed along the crutch, as the force vectors in the drawing indicate. If the coefficient of static friction between a crutch...