Recent content by MeAndMyLucidLife

Ya...Got It! V=IR All V, I, and R are mutually dependent. Keeping one of them constant gives us the relation between the other two. Thanks a lot:smile:

Yes! So in this problem, it was an understood fact that voltage remains constant. Thanks a lot!:smile:

Homework Statement : [/B] If the length of the filament of a heater is reduced by 10%, the power of the heater: Options are- a) increases by about 9%. b) increases by about 11%. c) increases by about 19%. d) decreases by about 10%. Homework Equations : P[/B]=I2R Or P=V2/R Where P=power...

Learned something new!:woot: Thanks a Lot:smile:

Beam 1 will have more photons! Okay! Got it! Beam 1 will have twice the number of photons than beam 2! so firstly on doubling the frequency, we are halving the intensity, and then on doubling the intensity, we end up with almost the same intensity as beginning! and thus the saturation current...

Oh yeah! E=hν Hence on doubling the frequency of a photon, we will double its energy! But this will only effect the maximum kinetic energy of the photoelectrons, and not the photocurrent. For the photocurrent is proportional to the no. of electrons coming out of the metal in unit time, and this...

yeah, E = n(hc/λ) where n denotes the no. of photons. Here, energy is dependent on the number of photons.

Definition: Intensity is like brightness, and is measured as the rate at which light energy is delivered to a unit of surface, or energy per unit time per unit area. Now in photoelectric effect, we only talk about the particle behavior of light. So in that sense, more intensity means more no...

This is the full question that i encountered. I think both the things, doubling of intensity and doubling of frequency, should effect the saturation photocurrent and cancel each other's effects for almost the same photocurrent. But I am not getting how?

Homework Statement If the frequency and intensity of a light source are both doubled, show that the saturation photo-current remains almost the same. 2. Relevant Graph https://cnx.org/resources/e73bf218926bd39de4a52bafe3a82d04bbf73542/CNX_UPhysics_39_02_photoexp1.jpg The Attempt at a Solution...

Don't get confused...Just make sure that the angle(theta) is measured from the horizontal. Then by the vector diagram, you will get T=mgSin(theta) + mv^2/r.

Now i got it!:biggrin: Thanks for making my concepts and terminology clearer... Thanks a lot!:smile:

All the answers are pretty convincing!:smile: Things which I learned are: We can't assume an inertial frame with respect to a photon! So we cannot take any inertial frame into consideration. I think this is because time and space are not defined for a photon. So, What should be the proper...

Homework Statement What is the speed of a photon with respect to another photon if: the two photons are going in the same direction. they are going in opposite direction? 2. The attempt at a solution I think the answer to the first question should be zero and to the second one be 2xC; C⇒speed...

Okay! Now I got it!:smile: Thanks a lot:-D