Recent content by meBigGuy

Where the DC content comes from that requires DC feedback path, for starters? If there is no DC input, why is DC path needed?

For LCD you can buy 7 LCD segments and place them in the correct geometry to save cost on the glass area (you pay by the overall area) Have you looked into Vacuum florescent displays?

I'm glad for you, but that's the way it works. Did you read the white paper? I know it's a bit short on hard technical details (to say the least), but that's essentially what it is saying. BTW, the waveform in Jim's post is Voltage. A standard transformer conducts into the filter caps at the...

At any point in time the triac can turn on and the transformer field (current) builds up. When the triac opens, the field collapses causing a voltage surge in the secondary which is captured by the filter capacitors.

http://www.flipdots.com/electromagnetic-large-7-segment-display.html#.Vwa41XolloE

There are two subjects being discussed, and confused. 1. How many bits to represent a quantity of symbols 2. How to code numbers in binary. Maybe my wording is not precise, but how many symbols one might use, and what people decide the symbols represent are, for the most part, orthogonal...

Can you explain why? ( in the context of a perfect amplifier with infinite input impedance, infinite gain, 0 offset, etc.)

I agree Your lowest power all electrical solution will probably be an LCD display with an LED side light. (I have not done the power analysis) For example, http://www.good-display.com/products_detail/&productId=141.html Microcontroller families generally have devices with LCD drivers...

Can you explain why in the context of a perfect amplifier with infinite input impedance, infinite gain, 0 offset, etc.

I misspoke, kinda. They are ideal differential voltage sources, not "real" opamps. No output impedence, no bias current, no offset, infinite gain, etc etc. Actually, using real models would solve his problem since those node would not be floating. Ironically that would change performance by...

They are not opamps. They are ideal circuit elements, so there is no such thing as bias current. Problem is that pspice will not simulate with floating nodes. For pspice, you need to add 100MegOhm resistors to ground on the floating nodes, other wise it can't find a quiescent solution to...

Ground as an input is no issue to me. I'm referring specifically to this: "This is because GND is supposed to indicate zero volts, but an op amp never puts out exactly zero volts, making the original label confusing" What is he trying to say? It's also wrong because op-amps put out exactly...

The 5 from the opamp to gnd is useless since OUT is 0 impedance. There needs to be a resistance fron the center node to ground or spice won't converge (possibly PSPICE puts it there automagically. Try 100MegOhms tp ground. No idea what "does not work" means. What was it supposed to do?

That doesn't make sense? What opamp ever had an output pin labeled ground?