Recent content by Mebmt

Where did the 10 ln 5 in the first line come from? I used 10 V * ln 5 to signify that ln 5 was half of the initial value. Instead I should have used 5 ΔV final=(ΔV initial)e^-t/τ 5 = 10e^-τ/.025s 0.5 = e^-τ/.025s ln 0.5 = -τ/.025 ln 0.5(.025) = -τ τ= 0.013 s Uc=0.5 C (ΔVc)^2 or...

1. Homework Statement The capacitor in an RC circuit with a time constant of 25 ms is charged to 10 V. The capacitor begins to discharge at t = 0 s 2. Homework Equations τ=RC ΔVC=(ΔVC)e^-t/τ 3. The Attempt at a Solution part a) At what time will the charge on the capacitor be...

Thanks Peter. The prof had changed the numbers on the website from those provided in the book. I had overlooked one of them.

1. Homework Statement 9 V battery is connected to wire made up of three segments of different materials connected in a series: 10 cm copper, then 12 cm iron, then 18 cm tungsten. All wires are 0.26 mm diameter. Find potential difference across each wire. Constants: p Copper= 1.7 x...

Yes, they are asking for x.

I didn't post the picture of the springs. It shows them as being parallel to each other with a platform on top. Sorry. My bad. I should be using them together. The link helped as well. Now, using Fspring=-kx 2250=(-)(2200+2200)x x=0.5 m

The x value is the total amount that the springs would be compressed by a force of 2250 N.

Using Hooke's law Fs=-kx 2250N=(-2200N/m)x x=1.02m 1.02m/2 springs =0.5 m

Then using Us=1/2kx^2 I have 1/2(2200)x^2=2250 x=1.43 One system meaning that there are 2 springs working identically to each other.

Given: Load of sacks have total weight of 2250 N and each sack weighs 225 N, how far will each of 2 springs in one system be compressed (spring coeff = 2200 N/m) when a sack is put on it? Energy init +work=final Energy 2250=1/2(4400)x^2 1.02=x^2 x=1.01 Not sure where to go from here.

Homework Statement Horizontal force of 210 N used to push 20 kg crate over 4 m with constant velocity. Looking for coefficient of kinetic friction.Homework Equations a=0 Work done by friction force is: Net force=ma Fapp-Fk=ma 210-Fk=0 Friction force = 210 The Attempt at a Solution friction...