Recent content by Meesh

Again, your equation is wavelength = speed / frequency. ( if you are unsure do a unit check... Does metres = [m/s]/(1/s) ? Yes. So you should just have 790/31200. Don't forget to look at the units to be sure... Or look at the equation. :)

Oh I understand. I think it is great that you are teaching yourself physics! I think the kinematic is your best bet in this case because it is the only way you can take velocity and acceleration into account. Good job. :)

Also those kinematic equations should have been posted in relevant equations if you are still using them in class. If you are doing kinematics, then use that equation.

How do you figure that the answer is d? Where did you get that answer from?

Why won't it be possible? Just too much room for messiness?

If the question were to ask what the intensity of the light was at a screen 1m away from your light source, then you would use the surface area of that screen, not the surface area of your light source (just to be clear on what surface area you are using -- not the surface area of your light...

Okay, so you need to be sure to have your units straight here... These are the same *numbers* as what I calculated... But not the same amount of zeros. At all. I measured this in meters, what is the units for your number?

Sonny18n, Do you know why you are using the speed of light in this question?

Thank you so much!

Hi there. I was redirected to ask on here where you can change the notification settings. As it is now, I am receiving loads of emails along with the alerts on the forum. However I would much rather just receive the alerts and no emails (as it is a school email and I am worried about missing...

I think it would be a good idea in the homework section, maybe not so much anywhere else. I think it is good for equations and to draw useful diagrams that suit the equations or the homework.

I agree. Something along the lines of radio frequency of a wave through a medium. Or something. You may want to start looking just purely at the em side of that though instead of light. Maybe take a look at Gauss's law and properties of a traveling wave. Sorry I couldn't come up with a...

Sorry update: the refractive index is independent of the wavelength that was a silly mistake on my part. The equation I gave you is universal. Basically the wavelength of your light changes inside the medium ( lambda = lambda naught/n ) where lambda is the wavelength and lambda naught is the...

It is constant within the medium. You want to look at the refractive index (n). In air, n=1. In a prism, it depends on the glass but generally, the more dense the medium the higher the refractive index (water: n=1.33 or something). I'm not sure about exactly at the point where the light bends...

Okay so how far back would you want your man to be thrown?