Recent content by Meshy

So I just realized it's just the multiplication of the 2 time increments. Obviously had too much on my mind today. lol. SOLVED.

Set - or * to t. x1 = 5, x2 = 4. f(x,y,t)=> f(5,4,2)=40; f(5,4,1)=20; f(x,y,t)=x*y*t So X*Y*T it is I guess. Lemme try, (2,3,1): 2X3X1 = 6 [SIZE="4"][FONT="Lucida Console"]-*-*-*-*-*-*-*-*-*-* --*--*--*--*--*--*--* Yup that's six increments. Wow. Figured it out myself :)

Looks like every 40 secs in that specific scenario.

Now that I think of it, if they were both 8 seconds they aren't guaranteed to ever communicate. But at 6 seconds, they should. Lemme give it another shot:-, * = 2 sec increments [FONT="Courier New"]...

Ok, so I had this thought for low power transistors to only broadcast certain data at specific time increments. I cannot figure out how to answer this for the heck of me. Two transceivers, and they only broadcast SEND requests when they have data to send. Transceiver A) Broadcasts every 8...