Recent content by metalclay

bit the bullet and just clicked "final check" and...*drumroll* it's right! Ha, thanks guys!

basically the area of a circle by its height dx substitute the equation f(y) = 4tan (pi*y/4) for r so r^2 is tan^2 which is (sec^2 - 1) found the integral by u substituting (pi*y/4) with u so you can now integrate sec^2 and 1 which gives tan (u) - u plugged those values in multiplied by...

yeah, sure. It's just that it's kind of long so didn't know if I should post: http://imgur.com/a/SaVJF

Homework Statement http://imgur.com/a/emr1n ∫01 x= 4tan(pi*y/4) , Find the volume of the solid by revolving shaded region about the y-axis Homework Equations tan^2=sec^2 - 1 The Attempt at a Solution I ended up with 64-16pi using u-substitution, not sure if right, want a confirmation. I only...

yeah, I know how I got the answer, but all I do to be honest is just follow rules and formulas. I don't really KNOW what I'm doing. But...I do understand your point. I guess I won't be able to check my answer then? argh. Also, ti-89 platinums can be entered without parametrization, I tried it...

Homework Statement Find dy/dx: ex2y=2x+2y Homework Equations Answer: 2(2xyex2y)/(x2ex2y-2) The Attempt at a Solution I'm not interested in the steps towards the answer, but more into being able to graph it and confirm it on a ti-84. The way I've been checking if my answer...