Recent content by MFlood7356

I got 5.86 J does that sound right?

so i would find the y and x components for each of the forces then add them up and use Pythagorean theorem then multiply that by the distance? For the angle of F2 should it be 270-51.6=218.4 degrees and should angle of F1 be 180 degrees?

Here's a diagram: http://imgur.com/DAJ8G.gif So would I find the magnitude of the components add them up then multiply that by the distance?

1. Figure 7-30 shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.28 N, F2 = 4.54 N, and F3 = 8.24 N, and the indicated angles are θ2 = 51.6° and θ3 = 35.8°...

Okay I understand that but that's the exact same thing I wrote. That's not helping me.

1. Define this method so that it adds the Strings in inputto an initially empty LRStruct<String> so that they appearin the same order. Example: if input contains "a", "b" and "c", in that order, the returned list must contain "a", "b" and "c", in that order. LRStruct Class...

Nope it was wrong :(

Well you copied my answers and that's all that matters you know

The exact wording is what is above for the question. Alright if youre sure I'll try it out.

Well here's a hint that I get from Wiley Plus Write Newton's second law for forces along a vertical y axis. Is the (centripetal) acceleration up or down? What is the gravitational force? (For safety, the car has wheels both above and below the track.)

So now were back to this as the answer? (1290(9.32)/20)-(1290*9.8)= -7063N (1290(182)/20)-(1290*9.8)= 8256N

So it should look like this? (1290(9.32)/20)+(1290*9.8)=18221N (1290(182)/20)+(1290*9.8)=33540N Sorry if I'm being annoying I'm on my last attempt for my online homework so I want to make sure it's correct before I submit it.

Oh so would I find the weight now and subtract them?

1. A roller-coaster car has a mass of 1290 kg when fully loaded with passengers. As the car passes over the top of a circular hill of radius 20 m, its speed is not changing. (a) At the top of the hill, what is the normal force (using the negative sign for the downward direction) FN on the car...

So I just tried it and still got it wrong. Here's what I did. a= 3.32/0.22= 49.5