What Is the Minimum Strength of a Fishing Line to Stop a Drifting Salmon?

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SUMMARY

The minimum strength of a fishing line required to stop a drifting salmon weighing 87 N over a distance of 11 cm, with an initial horizontal velocity of 3.3 m/s, can be calculated using Newton's laws of motion. The fish's mass is determined to be 8.89 kg, derived from the weight equation W=mg. To find the necessary deceleration, the formula v² - u² = 2as is applied, leading to an acceleration of 49.5 m/s². Consequently, the force needed to stop the salmon is calculated using F=ma, resulting in a minimum line strength of approximately 440 N.

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1. The tension at which a fishing line snaps is commonly called the line's “strength.” What minimum strength is needed for a line that is to stop a salmon of weight 87 N in 11 cm if the fish is initially drifting horizontally at 3.3 m/s? Assume a constant deceleration.

2. F=ma, W=mg

3. I have a feeling this problem is really easy I just don't know how to do it. I thought I did it correct below but my answer is wrong. Can someone help me please?

W=87N d=0.11m a+3.3m/s
m=87/9.8= 8.89kg
F=(3.3m/s)(8.89kg)= 29.3N
 
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I don't really understand how this can be a one-dimensional problem.
If it is, you first have to find the acceleration using what is given. ie.
Final velocity = 0
Initial velocity = 3.3 m/s
Displacement = 0.11 m
Try v2 - u2 = 2*a*s to find out the acceleration and multiply it with the mass of the body under consideration.
 
Oh okay. I had no idea I had to relate those equations. Is my mass that I have above correct?
 
So I just tried it and still got it wrong. Here's what I did.

a= 3.32/0.22= 49.5
 

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