Recent content by mHo2

Homework Statement My questions are as follows: (1) If I apply a force (B) on a beam with a center of gravity at the middle(A), it will JUST cause a moment, correct? (2) If I remove this fixed point(A), and no gravity or any other forces are present, will it still JUST cause a moment or will...

Yes, but I can't seem to simplify the equation I get.

It kind of does, however the magnitude of the z components is zero when it lies between the ring.

Homework Statement Hi, Having some trouble with answering this question: A thin nonconducting rod with a uniform distribution of +'ve charge 'Q' is bent into a circle of radius R. There is an axis, 'z' which originates in the center of this ring. In terms of 'R', at what +'ve value of...

Is a weak acids concentration determined from when it is in equilibrium, or if it hasn't dissociated at all? i.e. 0.100M CH3COOH. Would this be the concentration of CH3COOH during it's equilibrium: CH3COOH <-|-> CH3COO- + H+ Or just by itself? Thanks!

Okay so as an update my problem is: I can't differentiate between (as an example) 52C1*51C1 and 52C2 what's the intuitive difference? selection group? EDIT: Apparently it's due to order not mattering. My problem here is, the solution to this question, which is 13C1*4C3*12C2*4C1*4C1 I'm not...

In that case, I'm not sure how to write an algorithm for it. thanks for the help so far though!

I'm having trouble differentiating between 52C1*51C1, and 52C2, why are they not the same thing? Jack of Hearts Jack of Spades Jack of Clubs Thee of Spades Seven of Diamonds I would say the 6 choices that produce this hand would be: First rank is: Three The three accompanying suits...

Oh, sorry! 52C1*51C1 Brilliant! That's exactly how I'm viewing it in my head. I'm not sure where my logic fails. I suppose with the first two steps i would choose 13C1*4C3 This would pick a rank and then for the rank that was picked, choose three of the four suits for a combination...

I would say 52C2 so 1326

Homework Statement if three of the cards have the same face value and the other two have different face values? Homework Equations nCr or (n!)/((n-r)!(r!)) The Attempt at a SolutionSo far i have this for a solution (13C1) * (4C3) * (12C1) * (4C1) * (11C1) * (4C1) Where xCy is a...

I have tried graphing it, I was just being political. Any help? Bump!

Bumping, any help? Thanks!

I understand what is going on at that point conceptually, but not algebraicly. So I'm not sure if graphing it will help me out..

Okay, that makes sense, however my question is, why do we only want to deal with the upper bound and not the lower bound as well? I also think i understand this here, simply because if |x+2| has a maximum of 5 (rather infinitesimally close to 5) we can say that |x-2||x+2| will always be less...