Top of loop elevation = 2 * 0.36 = 0.72 m
Top of track= 1.2 m
Figure change in energy from top of track to top of loop
PE = KE
MGH = 0.5MV^2
5.4 * 9.8 * 1.2 = 0.5*5.4 V^2
2.7 V^2 = 63.504
V^2 = 23.52
V = 4.85 m/s
Fn = Force of Gravity - Centripetal Force
Fn = MG - M* (V^2/r)...
Homework Statement
A 5.4g mass is released from rest at C which has a height of 1.2m above the base of the loop-the-loop and a radius of .36m
Finde the normal force pressing on the track at A, where A is at the same level as the center of the loop. Answer in units of N
So the picture is of...
Applying Newton's 2nd law?!
Homework Statement
A 2.91 kg block starts from rest at the top of a 32◦ incline and slides 1.98 m down the incline in 1.28 s.
The acceleration of gravity is 9.8 m/s2
What is the acceleration of the block?
Answer in units of m/s2
What is the coefficient...