Recent content by mickjagger

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    Normal Force at a certain point in a loop

    Top of loop elevation = 2 * 0.36 = 0.72 m Top of track= 1.2 m Figure change in energy from top of track to top of loop PE = KE MGH = 0.5MV^2 5.4 * 9.8 * 1.2 = 0.5*5.4 V^2 2.7 V^2 = 63.504 V^2 = 23.52 V = 4.85 m/s Fn = Force of Gravity - Centripetal Force Fn = MG - M* (V^2/r)...
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    Normal Force at a certain point in a loop

    Homework Statement A 5.4g mass is released from rest at C which has a height of 1.2m above the base of the loop-the-loop and a radius of .36m Finde the normal force pressing on the track at A, where A is at the same level as the center of the loop. Answer in units of N So the picture is of...
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    Solving for Acceleration and Friction on an Inclined Plane

    using Vx=V cos Theta and Vy=Vsin theta: x component= 1.679? y component= 1.0492?
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    Solving for Acceleration and Friction on an Inclined Plane

    Applying Newton's 2nd law?! Homework Statement A 2.91 kg block starts from rest at the top of a 32◦ incline and slides 1.98 m down the incline in 1.28 s. The acceleration of gravity is 9.8 m/s2 What is the acceleration of the block? Answer in units of m/s2 What is the coefficient...