Recent content by Mike94

I meant to say that "s" is equals to 4.8697E-9 C Not quite sure what you meant by vertical velocity is just reversed. Do you mean that my final angle will be 90 degrees minus the angles from the final vertical component. Thanks.

After working for on it, I see it as a projectile: R=v0^2*sin(2*theta) / |ay| => 0.25 m = 5E6^2 * sin(2*theta) / 9.6718E13 m/s^2 theta equals to 37.64 degrees or 52.3599 degrees

E = 505 N/C E0 = 8.854 * 10^-12 C^2 / (Nm^2) E = s / E0 So my s should be 4.87E-9 uC / m^2 Fy = qE Fy = -1.602 * 10E-19 * 550 N/C Fy = 8.881E-17 N Fy = may 8.811E-17 N = 9.11 * 10E-31 kg * ay ay = 9.6718E13 m/s^2 x = x0 + v0x * t 0.25 m = 0 m + 5*10^6 * t t = 5E-8 s vy = v0y + ay * t vy =...

a) E = s / E0 so s is 4.87E-9 b) The electron will be projected at up angle since its charge is negative ( not sure if there's another reason behind it) c) Initial speed: V0 = 5 * 10^6 * cos(theta) + 5 * 10^6 * sin(theta)The force suffered by the electron is: Fy = q*Ey Fy = -1.602*10^19 *...

I'm using Ti-Nspire . I will use another calculator. Thanks a lot & have a wonderful day !

That's how I get it the numbers. Thank you.

Sorry, I was happy for nothing. Exhausted trying all day long to understand this. What I did was: kQ2Q1/d^2 + -kQ2Q3 / 2^2 = 0.054 F1,2+F1,3=-2*(F3,1+F3,2) Q1= 0.000005 & d =1 or Q1=0.000001 and d = -0.5 Which aren't the right numbers because F2,1 + F2,3 != 0.054

Thank you a lot! I think I got it. Q1 = 0.000238 D = 8.89898 By doing -k*q2*0.000238 / 8.89898^2 + k*q2*q3 / 2^2 = 0.081 , exactly what F2 is.

That's right. So, I can do: F1,2 = kQ1Q2 / d^2 F1,3 = -kQ1Q3 / (d+2)^2 F3,1 = kQ3Q1 / (d+2)^2 F3,2 = kQ3Q2 / 2^2 Doing a solve on F1,2 + F1,3 = - 2 (F3,1 + F32) to find q1 & d I'm surely missing something since the calculator cannot resolve. Thanks.

Minus signs is because Q2 & Q3 are pushing the Q1 to the left. KQ1Q2 / d^2 = KQ1Q3 / (d+2)^2 Which d = 2.73 and q1 = 0.000011 ? Thanks.

Not sure how about those equations, the only thing I see is: F1,2 = KQ1Q2 / -d^2 F1,3 = KQ1Q3 / (-d+2)^2 I really don't see another way to find equations related to the distance. If you can give me a hint to the right direction. Thanks again !

In order to get F2,1 = 0.081 I did: F2,1 + F2,3 = 0.054 F2,1 + -(F2,3 = 0.027 by using the Coulomb's law) = 0.054 So F2,1 = 0.081 I guess the distance ? Can I do F1 = F1,2 + F1,3 Set F1 to 0 and solve F1,2 = F1,3 in order to get the distance ? Thanks !

So, since F2,1 is 0.081 E2,1 = k|q2| / r^2 F2,1 = q1 * E2,1 Am I on the right track ? Thanks.

What do you mean by that ?

I need some help resolving the follow problem. I really don't know where to put the "twice as large as the resultant force on Q3" in order to build an equation. Thank you !