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Mike_bb reacted to Ibix's post in the thread Undergrad Why ##a^0=1##? with Informative.

Or, more generally, ##a^{n+m}=a^na^m## implies ##a^0=1##, because otherwise ##a^{n+0}\neq a^n##.

Apr 10, 2026
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Mike_bb reacted to Ibix's post in the thread Undergrad Why ##a^0=1##? with Like.

It's consistent with ##a^{n+1}=a\cdot a^n##

Apr 10, 2026
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Mike_bb posted the thread Undergrad Why ##a^0=1##? in Calculus.

Hello! I have problem in understanding why ##a^0=1##. I represent ##a^x## as ##1*a*a*a*a*...*a## (x times) Why ##a^0=1##? Why is...

Apr 10, 2026

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