Recent content by Mike_bb

Thanks to all! I catch an insight and now I understand how reciprocal time dilation works!

Dale, Sorry, but I can't provide complete sentence because I have no complete sentences in Russian examples.

Ok. Each of observers think that time in another frame is running slowly. And each of observers is right. This is proved by experiment: "Two observers fly to each other on the rockets and send light signal to each other every 2sec. Light signal every rocket receive with delay and this explain...

Matterwave, Let we have frame C with stationary clock C that shows some time. Compare clocks A , B on the fly at the time of clock C. We see that both clocks A , B show the same time in accordance with Postulate 1.

If you compare two clocks on the fly, you'll see that both clocks show 100sec.

Robphy gave good diagram and as I understand it corresponds to my explanation above ( He wrote that E1 and E4 are distinct).

No. I use Google AI that provides example with link to the sources. I tried to read Landau&Lifshitz.

Hello, PF! I just understand that people couldn't fully understand me in my old topic because many terms in English have another senses in Russian and vice versa. Because of the language barrier I couldn't explain what I meant. Moreover, my vocab is poor and I speak English badly. Please, sorry...

Thanks to all! I solved my problems! Please don't ban me.

frame A

That's the point, [clock A = 100s] and [clock B = 80s]. I suggest following simultaneously events: With reference to frame B the events [clock B = 125s] and [clock A = 100s]. Such way we have a contradiction because [clock A=100s] and [clock B=80s] are simultaneously events but [clock B = 125s]...

Yes, I agree with this, there is no contradiction. But why did you write about these events? I asked about that from frame B clock A shows 80s (as you mentioned in post#50) then clock A shows 100s. Which time does clock B show?

I provided example in post#69.

Well, see post #50: With reference to Observer B's rest-frame: Clock B first shows 80s (E2) and ##20s## later clock B shows 100s (E3). Clock A shows then ##100s/\gamma=80s##. With reference to Observer A's rest-frame: Clock B first shows 80s (E2) and ##\gamma20s## later clock B shows 100s...

If from frame B clock A shows 100s then in frame A clock A shows 100s. What's wrong?