Recent content by Mike_bb

Thanks to all! I solved my problems! Please don't ban me.

frame A

That's the point, [clock A = 100s] and [clock B = 80s]. I suggest following simultaneously events: With reference to frame B the events [clock B = 125s] and [clock A = 100s]. Such way we have a contradiction because [clock A=100s] and [clock B=80s] are simultaneously events but [clock B = 125s]...

Yes, I agree with this, there is no contradiction. But why did you write about these events? I asked about that from frame B clock A shows 80s (as you mentioned in post#50) then clock A shows 100s. Which time does clock B show?

I provided example in post#69.

Well, see post #50: With reference to Observer B's rest-frame: Clock B first shows 80s (E2) and ##20s## later clock B shows 100s (E3). Clock A shows then ##100s/\gamma=80s##. With reference to Observer A's rest-frame: Clock B first shows 80s (E2) and ##\gamma20s## later clock B shows 100s...

If from frame B clock A shows 100s then in frame A clock A shows 100s. What's wrong?

This is nice example. Thanks! But for our example you wrote that: From frame B: clock B shows 100s(E3), clock A shows 80s. Then clock A shows 100s, clock B shows 125s. But E1 (clock A shows 100s), E2(clock B shows 80s). 125s isn't equal to 80s. Where did I go wrong? THx.

Time doesn't depend on frames. Only time interval depends on the frames. (as in example above)

[clock A = 80s] and [clock B = 100s] -> [clock A = 100s] and [clock B = 80s]. clock a=80s -> clock a=100s - it's correct. But how is it possible that clock b = 100s -> clock=80s ? The clock is running backwards.

Case 1) Reference frame: A E1: clock A shows 100s E2: clock B shows 80s Case 2) Reference frame: B E3: clock B shows 100s E4: clock A shows 80s You wrote that clock A = 80s (when clock B =100s) but clock A = 100s when clock B=80s (case1). It means that E2 < E3 when E4<E1. (contradiction)

Big thanks!! This solved my problem! But is your last edited version correct? I mean "Clock A shows then ##100s/\gamma=80s##." and "Clock A shows then ##\gamma100s=125s##."? Clocks can't show two different time.

Let we have 2 events. In the 1st IRF these events happen simultaneity, but in the 2nd moving IRF these events happen at the different time.

Dale, I've read about the relativity of simultaneity but I can't understand how does it apply to example with observers.

Yes. But I used them several times.