Recent content by mlee

hey who can help me with this physics problem? A particle of mass m is in the state: Ψ (x, t) = Aexp[-a(sqrt (mx^2) / h)-i (at / sqrt(m )) ] where A and a are positive real constants. a) Determine A. b) What is the frequency ƒ associated with the wave function of this particle? Explain...

who cam help me with this wave problem?? A wire consists of two sections. For x > 0 the mass density of the wire is greater than for x < 0. The tension in the wire is the same everywhere. When waves propagating along this wire in the positive x direction reach x = 0, part of the wave is...

Hey dearest people Who can help me solve the following problem? A wave pulse is described by, y = 0.04exp(-0.6(68x - 7600t)2) [m]. Here t is measured in seconds, x and y are measured in meters. a) What is the velocity of this wave pulse? Be careful to get the sign of the velocity...

Pls who can help me with this following problem? A real heat engine operates between temperatures Tc and Th. During a certain time, an amount Qc of heat is released to the cold reservoir. During that time, what is the maximum amount of work that the engine might have performed? Thank you

Hi people, Who can help me solve this problem? One mole of an ideal monatomic gas at STP first undergoes an isothermal expansion so that the volume at point b is 2.5times the volume of point a. Next, the heat is extracted at a constant volume so that the pressure drops. The gas is then...

thank you very much

a) Q= kA(T_H-T_L)/h, where k=0.040W/(mK),A= 1.8m^2, h=1.2x10^-2m, T_H= 33, T_L=1 Q= 1830 Watts b) Q= 22875 Watts IS this right>??

Dear people, Who can help me with this physics problem? A skier is sitting on top of the mountain on a windless day. The sky is cloudy and the principal loss of her body heat is due to conduction. Her body temperature is 33 degrees of celsius and the air temperature at the surface of her...

b is unknown

cos phi is 0.333? is that right?

and w' = 5*10^2-(b^2/1*10^-2) is that right?

i don't know how to find phi

ω = sqrt(k/m) ω' = √((k/m) - (b²/4m²))

Ae^(bt/2m)*cos(w't+φ)

Ae-bt/2mCos(ω't + φ)