Recent content by mmattson07

Or 39.84 pF?

Still confused...how do I convert then? Is it 3.984e-12 pF??

Homework Statement The plates of a spherical capacitor have radii 30.3 mm and 33.1 mm. (a) Calculate the capacitance in picofarads. (b) What must be the plate area in square centimeters of a parallel-plate capacitor with the same plate separation and capacitance? Homework Equations C=...

Yeah. Luckily I found that somewhere else or I'd still be lost. I don't know what the direction is , don't care to find it because the question doesn't ask for it. But it will have something to do with arctan(y/x) ;)

Nobody could point this out I guess but m*v=0.5m*u 2v=u So the new speed is twice the initial

Apparently the new speed is 2(13.52m) ?

just realized I posted this twice. My apologies.

Homework Statement A shell is shot with an initial velocity 0 of 23 m/s, at an angle of θ0 = 54° with the horizontal. At the top of the trajectory, the shell explodes into two fragments of equal mass (Fig. 9-42). One fragment, whose speed immediately after the explosion is zero, falls...

Looks good.

You know the initial K and U and u know at the max compression of the spring the energy is just the elastic potential energy 1/2kx^2 and you can set them equal because the energy is conserved

Energy is conserved when the block compresses the spring. So you can set up an equation to solve for the max distance d the spring will compress.

oh NVM

I'm stumped. Here is what the hint reads: "You then need to set up an energy equation: initial mechanical energy - energy transferred to thermal energy = final mechanical energy." So I have been trying: 106J-(mg/cos27)(0.42)d=mgdsin27 =>d=106J/(mgsin27+(mg/cos27)(0.42)) with mg/cos27 being...

Not getting the correct answer. d= 106J/((2.7kg)(9.8m/s^2)sin27-0.42) `=9.144 m The correct answer is 4.837m

Ok, so we have 106J+0J=mgdsin27-(0.42)d =>106J= d(mgsin27-0.42) =>d=106J/(mgsin27-0.42) Just realized: we can assume Kf=0 because the bundle will be stopped?