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Graduate ODE y''+b^2 y=0 where b is vector
Hi, please help me with this task. I'm wondering what is the right result. I have a ODE y'' - b^2 y =0 also the result should be y=C e^{\pm bx} but what is the result when b is vector? \vec b=(b_x, b_y) is this the result? y=C e^{\pm \vec{b}x} or this? y=C e^{\pm |b| x}...- mogul
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- Ode Vector
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- Forum: Differential Equations