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please help me with this task. I'm wondering what is the right result.

I have a ODE

[itex]y'' - b^2 y =0[/itex]

also the result should be

[itex]y=C e^{\pm bx}[/itex]

but what is the result when b is vector?

[itex]\vec b=(b_x, b_y)[/itex]

is this the result?

[itex]y=C e^{\pm \vec{b}x}[/itex]

or this?

[itex]y=C e^{\pm |b| x}[/itex]

how to solve it?

thanks for help!

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# ODE y''+b^2 y=0 where b is vector

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