Recent content by mohamad hajj

the V- is not connected. (even not connected to ground reference) the voltage at V- is zero or +2.5 volts like V+ or what? thank you

suppose an amplifier with V+ is 2.5 volts and V- is not connected...V- and Voutput are connected by a resistor. what is the voltage on the outpout of the op amp?

Oh sorry ! it's automatic power system*..briefly..it's a transformer that trasforms 12 volts to 220 volts .we use it when the electricity is off.. so when electicity is on, the 12volts battery charges.and when the electricity cuts off,we turn the APS on ( or maybe automatically) to get the 220...

why does the APS (Automatic power system) consumes much current uppon starting on? so its known to prevent much turning the APS ON and OFF?

you can choose any sense of the loops(clockwise,anticlockwise,or both).it doesn't affect the final result..but for each sense of the loop in a mesh,u have to form the kirchhoffs equation according to the loop's sense you put... u finally get a system of equations with several unkowns... take...

yes,the voltage across a wire is zero,since its points are considered the same, so the potential difference is zero... it can be also proved by Ohm's law( V=IR )...the resistance of the conductibg wire is almost zero,then V=0.

yes sure V=IR is always valid (thats Ohm's law giving ralation between V and I across any resistor)... but the above method (mesh analysis) gives u directly all the currents you need in any branch of the circuit..and so, you can get V across each resistor (using Ohms law V=IR)... i think its...

yes I1=0.779 A...where is the problem? this the current traversing R1 (from left to right) and this current also traversing 9.8ohm (from right to left).. same way u calculate I2 (in the second mesh and in clock wise direction)...which is the current traversing 6.7 ohm...then ( I1-I2 ) is...

u can solve it using mesh analysis or by superposition law... lets solve it using mesh analysis: consider the left mesh with I1 traversing it in clockwise direction: then: 12v=I1(R1+1.2+9.8) so u can get I1 consider the right mesh with I2 traversing it also in clock wise direction: then...