Yes, it is a projectile motion question, sorry about that!
Okay, so is the 3.03cm in the x direction then? So do I just do t = d/v and solve for t, with d being 3.03 cm and v being 4.12×10^6 m/s? Or is it the v in the x direction that I use?
I'm still slightly confused..I understand the...
Homework Statement
An electron is launched at a α=38.5° angle and speed of 4.12×10^6 m/s from the positive plate of the parallel plate capacitor shown. If the electron lands d=3.03 cm away, what is the electric field strength inside the capacitor?
Homework Equations
t = d/v
v0y =...
Ahh, I see I was not using the correct time for t(max), I was using the time it takes for it to return to the initial position. So I solved the maximum height to be 1.22 x 10^-3 m, and that is correct. I now only need help on finding the displacement!
Homework Statement
An electron is projected at an angle of 29.1° above the horizontal at a speed of 8.29×105 m/s in a region where the electric field is E = 378j N/C. Neglecting the effects of gravity, calculate the time it takes the electron to return to its initial height, the maximum height...
Homework Statement
A rod has one end at the origin and one end at the point P whose coordinates are (1m, 2m, 2m). A force F = (3i+2j-1k) N acts on the rod at the point P. What is the torque about the origin due to F?
Homework Equations
torque = F x r
The Attempt at a Solution
I'm...
Oh I apologize; the graph is simply a straight diagonal line showing constant velocity, but the problem is, there are no numbers on the axes, so I need to find another way to find average velocity.
Homework Statement
The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00 s and reaches a maximum velocity, vmax, after a total elapsed time, total. If the initial position of the particle is x0=6.00 m, the maximum velocity of the particle...