Recent content by momowoo

Yes, very interesting haha. Thank you!

https://drive.google.com/file/d/0B_PrsFZNgMynZWtvVXRFS3JHX0E/view?usp=sharing

https://drive.google.com/file/d/0B_PrsFZNgMynZWtvVXRFS3JHX0E/view?usp=sharing

I'm unsure how to go about doing that. Do I use the bulb wattage as the power, or should I not because that isn't the true power they dissipate?

Resistance would be 110 ohms.

Homework Statement Two 110-V light bulbs, one "25W" and the other "100W" are connected in series to a 110 V source. Then: a. the current in the 100W bulb is greater than in the 25W bulb b. the 25W bulb will be brighter c. the current in the 100W bulb is greater than that in the 25W bulb d. the...

THANK YOU SO MUCH FOR HELPING ME <3

So does this mean that a positive slope means moving to the left and neg slope means moving to the right?

To the left?

its like when x is equal to 0(the reference point) that is some distance to the left of the pos charge right?

ohhhhh. So in that case, the region defined by the positive slope is probably to the left of a positive test charge. The area in which there is a constant V value is at the charge and then the negative slope would be to the right of the test charge because there is lower PE the larger the x value.

How do you define field direction? Wouldn't saying left and right be arbitrary?

ohhh so if the graph shows a positive slope then the test charge would be moving towards the positive charge and if its negative then it would be moving away?

towards lower potential

Would that be a hollow sphere?