Recent content by mpgcbball
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Calculate nth Degree Taylor Polynomial for f(x)=sqrtx | Taylor Polynomial Help
for any function in general...thanks!- mpgcbball
- Post #7
- Forum: Calculus and Beyond Homework Help
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Calculate nth Degree Taylor Polynomial for f(x)=sqrtx | Taylor Polynomial Help
is there a general method to finding the nth degree polynomial? or is it always just f^n(a)x^n/nfactorial ?? Thanks!- mpgcbball
- Post #6
- Forum: Calculus and Beyond Homework Help
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Calculate nth Degree Taylor Polynomial for f(x)=sqrtx | Taylor Polynomial Help
but is what i wrote for P(x) the nth degree polynomial? Thanks- mpgcbball
- Post #3
- Forum: Calculus and Beyond Homework Help
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Calculate nth Degree Taylor Polynomial for f(x)=sqrtx | Taylor Polynomial Help
Homework Statement I'm trying to make the nth degree taylor polynomial for f(x)=sqrtx centered at 4 and then approximate sqrt(4.1) using the 5th degree polynomial I know that the polynomials are found using the form: P(x)= f(x)+f'(x)x+f''(x)x^2/2factorial...f^n(x)x^n/nfactorial so...- mpgcbball
- Thread
- Polynomial Taylor
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Mastering Improper Integrals: Convergence & Divergence Techniques
Hi, I'm having a bit of trouble showing that the integral from 1 to infinity of x/((1+x^6))^1/2 converges or diverges by the comparative property. I'm not sure if I'm setting it up right, but so far I have that 1/rad(1+x^6) is less than or equal to x/rad(1+x^6) which is less than 1/rad(x^6)...- mpgcbball
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- Improper integral Integral
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Integrating arctan(1/x) with Integration by Parts
im still getting stuck at xarctan(1/x)-int(-x/x^2+1)- mpgcbball
- Post #7
- Forum: Calculus and Beyond Homework Help
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Integrating arctan(1/x) with Integration by Parts
ooooh i get it! thank you- mpgcbball
- Post #6
- Forum: Calculus and Beyond Homework Help
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Integrating arctan(1/x) with Integration by Parts
that doesn't make any sense to me, but thankyou for trying to help. i don't know what "it" is referring to that I am supposed to be taking as 1*arctan(?)- mpgcbball
- Post #5
- Forum: Calculus and Beyond Homework Help
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Integrating arctan(1/x) with Integration by Parts
im not really understanding how to get that line. i don't know what to assign as u and dv. the xarctan1/x is the part that confuses me because i don't see where the x comes from- mpgcbball
- Post #3
- Forum: Calculus and Beyond Homework Help
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Integration by parts with my work
Homework Statement integrate arctan(1/x) Homework Equations The Attempt at a Solution z=arctan(1/x) dx=-dz(x^2-1) now its the integral of z(x^2-1)dz let u =X^2-1 du=2x dv=-udu v=-u^2/2 integral=(x^2-1)(-u^2/2) - int (-u^2)(2x) this is where i got stuck but i...- mpgcbball
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- Integration Integration by parts parts Work
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Integrating arctan(1/x) with Integration by Parts
im having a bit of trouble, can anyone help me integrate arctan(1/x) using integration by parts? thanks- mpgcbball
- Thread
- Integration Integration by parts parts
- Replies: 9
- Forum: Calculus and Beyond Homework Help