Recent content by mrapple

I know that force times distance on each side is used to calculate equilibrium. What I am trying to figure out is if the heavier side will always cause it to point straight downward or somewhere in between at an angle not perpendicular to the ground?

Turbine. Perpetual motion machines don't work

Terms to google I am trying to produce a water fed engine. This isn't homework. I do not have a physics degree. I can't find the answer online as when you google equilibrium they all refer to a situation where the rod is perpendicular to the ground. You said it won't make a difference at a...

Do I use Sin instead if the angle is decreasing right?

Just so I can google the equation. I will do it on my own.

(mass)(g)*cos(45)? I have no idea where to start. If you could direct me a little I will try to read up on it on my own. I just need someone to get me started.

a float with 5 pounds of water displacement is resting on the bottom of a pool of water 10 feet deep. The float is tethered to the bottom of the pool via a string that is pulled tight lengthwise and so is also laying on the bottom of the pool. The string is 4 feet long. If the float is...

Also, a float with 5 pounds of water displacement is resting on the bottom of a pool 10 feet deep. The float is tethered to the bottom of the pool via a string that is pulled tight lengthwise and so is also laying on the bottom of the pool. The string is 4 feet long. If the float is released...

The buoyant object is being pushed into a hole at the bottom a tub of water 40 feet below the surface of the water. This object is being pushed in at a 45 degree angle downward. What equation do I use to find out the force needed to push the object into the tub of water neglecting friction?

When using a lever the movement is in the shape of an arch. Do I use cos (for example) to calculate the force for both the output and the input? If not, why? Thanks

I would say hydrostatic pressure is only important for a closed system such as a pipe where a denser fluid rises on the other side when pushing a less dense fluid. I would say regular water pressure would be the force required to plug a hole because it is from the side and not dependent upon...

Thanks. To follow up, I have a container of water 35 feet deep. If I push a cubic foot container of air into the side of the tank of water 30 feet below the surface I use hydrostatic pressure not water pressure to figure out resistance correct?

Thank you!

Yes but I'd like to make the question simpler. If an Enclosed Cubic foot capsule passing between two bodies of different densities but equal pressure there will be no resistance right?

Given equal pressure even though the densities are different the capsule won't move.