Recent content by MrAwojobi

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    Graduate Simple Proof of Fermat's Last Theorem and Beal's Conjecture

    ramsey2879 I have added an extra paragraph to my article and this offers more explanations to my claims.
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    Graduate Simple Proof of Fermat's Last Theorem and Beal's Conjecture

    I have revamped the proof again so that n is not required to be odd.
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    Graduate Simple Proof of Fermat's Last Theorem and Beal's Conjecture

    I forgot to mention that n is odd and A and B are not necessarily integers in the transformation. This slight ammendments are in this new attachment.
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    Graduate Simple Proof of Fermat's Last Theorem and Beal's Conjecture

    Attached is the proof.
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    Graduate Revised Simple Proof of the Beal's Conjecture

    Hi y'all I believe this latest write up of the proof should make more sense. Tell me what you think by reviewing the attachment. Many thanks.
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    Graduate Revised Simple Proof of the Beal's Conjecture

    CRGreathouse not you again! You seem to be everywhere (I bet you're thinking to yourself 'see who's talking'). I would prefer that your responses are based on proper mathematical criticisms. I thought that this is what maths forums are all about when I discovered them about a month ago or...
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    Graduate Revised Simple Proof of the Beal's Conjecture

    jgens just as you say that 'this isn't a proof', I say to you that your response to my proof is a non-response because you haven't elaborated on why you make this statement. I guess you just can't believe that a $100 000 prize problem ended up being so simple. I am one of a very few...
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    Graduate Revised Simple Proof of the Beal's Conjecture

    jgens maybe the best way I should have explained this was to say that for(A+B)(A^2-AB+B^2)to be a number raised to a power of 4 or greater (Fermat's last theorem doesn't permit a power of 3)then it must factorise further i.e. A and B must have at least a common factor.If they don't then...
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    Graduate Revised Simple Proof of the Beal's Conjecture

    jgens you are telling me to prove general statements which I do not need to. All I am saying is that for those types of examples I have listed in the proof, i.e. after numbers have been substituted into the equation, then the claims I make must hold.
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    Graduate Revised Simple Proof of the Beal's Conjecture

    SIMPLE PROOF OF BEAL’S CONJECTURE (THE $100 000 PRIZE ANSWER) Beal’s Conjecture Beal’s conjecture states that if A^x + B^y = C^z where A, B, C, x, y and z are positive integers and x, y and z are all greater than 2, then A, B and C must have a common prime factor. Examples...
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    Graduate Simple Proof of Beal's Conjecture

    JCVD This is not a criticism. It contains no highlights of the so called several errors/gaps in logic, which when removed/corrected, leave it, at best, a restatement of the conjecture.
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    Graduate Simple Proof of Beal's Conjecture

    Hi all, I have added an equation to the revised proof to show why the Pythagorean triples don't obey Beal's equation. SIMPLE PROOF OF BEAL’S CONJECTURE Beal’s Conjecture Beal’s conjecture states that if A^x + B^y = C^z where A, B, C, x, y and z are positive integers and x, y and z are...
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    Graduate Simple Proof of Beal's Conjecture

    Hi all, I have slightly altered my proof and I actually believe it is correct. Please before criticising it, read it carefully first. SIMPLE PROOF OF BEAL’S CONJECTURE Beal’s Conjecture Beal’s conjecture states that if A^x + B^y = C^z where A, B, C, x, y and z are positive integers and...
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    Graduate Simple Proof of Beal's Conjecture

    Hi viwers I think I have to concede that my proof is not water tight based on an issue. Since a^3 + b^3 and a^3 - b^3 also factorise in a unique way just like Pythagoras theorem equation factorises in its own unique way, then counter examples to Beal's conjecture could be searched for based...
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    Graduate Simple Proof of Beal's Conjecture

    SIMPLE PROOF OF BEAL’S CONJECTURE (THE $100 000 PRIZE ANSWER) Beal’s Conjecture Beal’s conjecture states that if A^x + B^y = C^z where A, B, C, x, y and z are positive integers and x, y and z are all greater than 2, then A, B and C must have a common prime factor. Examples...